8x^2-68x-120=0

Solution for 8x^2-68x-120=0 equation:

8x^2-68x-120=0

a = 8; b = -68; c = -120;
Δ = b2-4ac
Δ = -682-4·8·(-120)
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-92}{2*8}=\frac{-24}{16}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+92}{2*8}=\frac{160}{16}
=10
$